Решите систему уравнений cases(x)/(sin(x^2-y^2))-y*ctg(x^2-y^2)=sqrt((5pi)/(6)) (y)/(sin(x^2-y^2))-x*ctg(x^2-y^2)=sqrt((pi)/(2))cases

x = \frac{2\sqrt{5}+\sqrt{3}}{3\sqrt{2}}\cdot\sqrt{\pi},\ y=\frac{\sqrt{5}+2\sqrt{3}}{3\sqrt{2}}\cdot\sqrt{\pi}