Решите систему уравнений cases(x)/(sin(x^2-y^2))+y*ctg(x^2-y^2)=sqrt((2pi)/(3))[2mm] (y)/(sin(x^2-y^2))+x*ctg(x^2-y^2)=-sqrt((pi)/(2))cases

x = 7\sqrt{\dfrac{\pi}{6}},\ y=-2\sqrt{2\pi}