Решите неравенство _3(1-x) - _3(1+x) + _(1+x)(1-x) - 1 0 .

Заметим, что О.Д.З. x равна (-1, 0) U (0, 1) . Тогда _3(1-x) - _3(1+x) + _(1+x)(1-x) - 1 0 _3(1-x) - _3(1+x) + (_3(1-x) - _3(1+x))/(_3(1+x)) 0 (( _3(1-x) - _3(1+x) )( _3(1+x) + 1 ))/(_3(1+x)) 0 cases (( (1-x) - (1+x) )( (1+x) - (1)/(3) ))/(x) 0 x in (-1, 0) U (0, 1) cases cases x -(2)/(3) x in (-1, 0) U (0, 1) cases x in [ -(2)/(3), 0 ) U (0, 1).

x \in \left[ -\frac{2}{3}, 0 \right) \cup (0, 1)