Решите уравнение 2 * (sin 3x - sin x)/(cos 3x + cos x) = sqrt(3) * ( 1 - tg^2 x ) .
2 * (sin 3x - sin x)/(cos 3x + cos x) = sqrt(3) * ( 1 - tg^2 x ) 2 * (cos 2x sin x)/(cos 2x cos x) = sqrt(3) * (cos 2x)/(cos^2 x) tg 2x * (cos x)/(cos x) = sqrt(3) 2x = (pi)/(3) + kpi, k in Z x = (pi)/(6) + (kpi)/(2), k in Z
\( x = \pi/6 + k\pi/2, \ k \in \mathbb{Z} \)