Решите неравенство 8 + _(sqrt(x)) 8 4_x sqrt(17x^2 - 2) .
8 + _(sqrt(x)) 8 4_x sqrt(17x^2 - 2) _x(8x^4) _x(17x^2 - 2) cases x > sqrt(2/17) (8x^4 - 17x^2 + 2)/(x - 1) 0 cases cases x > sqrt(2/17) ((8x^2 - 1)(x^2 - 2))/(x - 1) 0 cases x in (sqrt((2)/(17)), (1)/(sqrt(8))] U (1, sqrt(2)].
\( x \in \left(\sqrt{\frac{2}{17}}, \frac{1}{\sqrt{8}}\right] \cup (1, \sqrt{2}] \)